Universal Generalization

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ƒy / (x)ƒx UG where the VARIABLE y is free in ƒy in EXACTLY those places that x is bound in ƒx by the quantifier (x)

CORRECT

1.
2.
(x)Axy
(y)(x)Axy

1,UG

INcorrect

1.
2.
(x)Axy
(x)Axx

1,UG

X since the (x) controls the place where y was free and others as well.

CORRECT

...
7.
8.

Axa
(z)Aza


7,UG

INcorrect

...
7.
8.

Axa
(y)Axy


7,UG


X since a is NOT an x y z

CORRECT

1.
2.
3.
4.
(∃y)[Ax • By]
Ax • Ba
Ax
(x)Ax

1,EI
2,simp
3,UG

INcorrect

1.
2.
3.
(∃y)Axy
Axa
(x)Axa

1,EI
1,EI


X since line #3 contains a and x is free in line #2 where a was introduced.

CORRECT

3. Ax
|4. Bx
|5. Bx • Ax
ACP
4,3,conj
6.
7.

Bx ⊃ (Bx•Ax)
(x)[Bx ⊃ (Bx•Ax)]
CP 4-5
6,UG

INcorrect

3. Ax
|4.
|5.
Bx
(x)Ax
ACP
3 UG

X since this UG is within the scope of an ACP (or AIP) and x is free in the ACP (AIP).