Calculates the probability of the occurrence of an event given the probability of its nonoccurrence (or the reverse).
For example, the probability of getting at least one ace in two draws from a standard deck is the negation of not getting an ace at all. The latter is 48/52 * 47/51 or 188/221. So, P(at least one ace in 2 draws) = 221/221 - 188/221 or 33/221.